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Part 1 - How to find nth highest salary in sql
1. Employees table contains the following columns Here is the problem definition:
a) EmployeeId,
b) EmployeeName
c) ManagerId
2. If an EmployeeId is passed, the query should list down the entire organization hierarchy i.e who is the manager of the EmployeeId passed and who is managers manager and so on till full hierarchy is listed.
Consider the following organization hierarchy chart
For example,
Scenario 1: If we pass David's EmployeeId to the query, then it should display the organization hierarchy as shown below.
Scenario 2: If we pass Lara's EmployeeId to the query, then it should display the organization hierarchy as shown below.
We will be using the following Employees table for this demo
SQL to create and populate Employees table with test data
Here is the SQL that does the job
Part 1 - How to find nth highest salary in sql
1. Employees table contains the following columns Here is the problem definition:
a) EmployeeId,
b) EmployeeName
c) ManagerId
2. If an EmployeeId is passed, the query should list down the entire organization hierarchy i.e who is the manager of the EmployeeId passed and who is managers manager and so on till full hierarchy is listed.
Consider the following organization hierarchy chart

For example,
Scenario 1: If we pass David's EmployeeId to the query, then it should display the organization hierarchy as shown below.

Scenario 2: If we pass Lara's EmployeeId to the query, then it should display the organization hierarchy as shown below.

We will be using the following Employees table for this demo

SQL to create and populate Employees table with test data
Create table Employees
(
EmployeeID int primary key identity,
EmployeeName nvarchar(50),
ManagerID int foreign key references Employees(EmployeeID)
)
GO
Insert into Employees values ('John', NULL)
Insert into Employees values ('Mark', NULL)
Insert into Employees values ('Steve', NULL)
Insert into Employees values ('Tom', NULL)
Insert into Employees values ('Lara', NULL)
Insert into Employees values ('Simon', NULL)
Insert into Employees values ('David', NULL)
Insert into Employees values ('Ben', NULL)
Insert into Employees values ('Stacy', NULL)
Insert into Employees values ('Sam', NULL)
GO
Update Employees Set ManagerID = 8 Where EmployeeName IN ('Mark', 'Steve', 'Lara')
Update Employees Set ManagerID = 2 Where EmployeeName IN ('Stacy', 'Simon')
Update Employees Set ManagerID = 3 Where EmployeeName IN ('Tom')
Update Employees Set ManagerID = 5 Where EmployeeName IN ('John', 'Sam')
Update Employees Set ManagerID = 4 Where EmployeeName IN ('David')
GO
Here is the SQL that does the job
Declare @ID int ;
Set @ID = 7;
WITH
EmployeeCTE AS
(
Select EmployeeId, EmployeeName,
ManagerID
From Employees
Where EmployeeId = @ID
UNION ALL
Select Employees.EmployeeId ,
Employees.EmployeeName,
Employees.ManagerID
From Employees
JOIN EmployeeCTE
ON Employees.EmployeeId =
EmployeeCTE.ManagerID
)
Select E1.EmployeeName, ISNULL(E2.EmployeeName, 'No Boss') as ManagerName
From
EmployeeCTE E1
LEFT Join EmployeeCTE E2
ON E1.ManagerID = E2.EmployeeId
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